How do you find the limit lim_(x->-4)(x^2+5x+4)/(x^2+3x-4) ?
1 Answer
Jul 29, 2014
=3/5 Explanation,
Using Finding Limits Algebraically,
=lim_(x->-4)(x^2+5x+4)/(x^2+3x-4) , if we plugx=-4 , we get0/0 form
=lim_(x->-4)(x^2+4x+x+4)/(x^2+4x-x-4)
=lim_(x->-4)(x(x+4)+1(x+4))/(x(x+4)-1(x+4))
=lim_(x->-4)((x+4)(x+1))/((x+4)(x-1))
=lim_(x->-4)((x+1))/((x-1))
=(-3)/-5
=3/5