How do you find the limit lim_(x->-4)(x^2+5x+4)/(x^2+3x-4) ?

1 Answer
Gaurav
Jul 29, 2014

=3/5

Explanation,

Using Finding Limits Algebraically,

=lim_(x->-4)(x^2+5x+4)/(x^2+3x-4) , if we plug x=-4, we get 0/0 form

=lim_(x->-4)(x^2+4x+x+4)/(x^2+4x-x-4)

=lim_(x->-4)(x(x+4)+1(x+4))/(x(x+4)-1(x+4))

=lim_(x->-4)((x+4)(x+1))/((x+4)(x-1))

=lim_(x->-4)((x+1))/((x-1))

=(-3)/-5

=3/5

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