How do you find the limit lim_(x->3^+)|3-x|/(x^2-2x-3) ? Calculus Limits Determining Limits Algebraically 1 Answer Wataru Sep 14, 2014 For x>3, we can write |3-x|/{x^2-2x-3}={x-3}/{(x-3)(x+1)}=1/{x+1} So, lim_{x to 3^+}|3-x|/{x^2-2x-3} =lim_{x to 3^+}1/{x+1}=1/{3+1}=1/4 Answer link Related questions How do you find the limit lim_(x->5)(x^2-6x+5)/(x^2-25) ? How do you find the limit lim_(x->4)(x^3-64)/(x^2-8x+16) ? How do you find the limit lim_(x->2)(x^2+x-6)/(x-2) ? How do you find the limit lim_(x->-4)(x^2+5x+4)/(x^2+3x-4) ? How do you find the limit lim_(t->-3)(t^2-9)/(2t^2+7t+3) ? How do you find the limit lim_(h->0)((4+h)^2-16)/h ? How do you find the limit lim_(h->0)((2+h)^3-8)/h ? How do you find the limit lim_(x->9)(9-x)/(3-sqrt(x)) ? How do you find the limit lim_(h->0)(sqrt(1+h)-1)/h ? How do you find the limit lim_(x->-4)((1/4)+(1/x))/(4+x) ? See all questions in Determining Limits Algebraically Impact of this question 10670 views around the world You can reuse this answer Creative Commons License