How do you find the derivative of #y= ln(1 + e^(2x))#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Other Bases 1 Answer GiĆ³ Apr 28, 2015 You can use the Chain Rule to derive #ln# first (as it is) and then multiply by the derivative of the argument as: #y'=1/(1+e^(2x))*2e^(2x)=(2e^(2x))/(1+e^(2x))# Answer link Related questions How do I find #f'(x)# for #f(x)=5^x# ? How do I find #f'(x)# for #f(x)=3^-x# ? How do I find #f'(x)# for #f(x)=x^2*10^(2x)# ? How do I find #f'(x)# for #f(x)=4^sqrt(x)# ? What is the derivative of #f(x)=b^x# ? What is the derivative of 10^x? How do you find the derivative of #x^(2x)#? How do you find the derivative of #f(x)=pi^cosx#? How do you find the derivative of #y=(sinx)^(x^3)#? How do you find the derivative of #y=ln(1+e^(2x))#? See all questions in Differentiating Exponential Functions with Other Bases Impact of this question 5550 views around the world You can reuse this answer Creative Commons License