How do I find f'(x) for f(x)=5^x ?
4 Answers
Apr 4, 2018
dy/dx = 5^x log5
Explanation:
y=5^x
logy=x log5
dy/dx. 1/y=x.(0)+log5.(1)
dy/dx . 1/y =log5
dy/dx =log5 . y
dy/dx =log5 . 5^x
dy/dx = 5^x log5
Apr 4, 2018
Taking log on both the sides,
Now, applying implicit differentiation,
Apr 4, 2018
Explanation:
Let
then
or
Apr 4, 2018
Explanation:
Given:
Using the common integral that