What is the value of Keq?

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1 Answer
Truong-Son N.
Mar 1, 2018

Well, this is based on a known #x#.

#2"SO"_2(g) " "" "+" "" ""O"_2(g) " "rightleftharpoons" " 2"SO"_3(g)#

#"I"" "0.0250" "" "" "" "" "0.0200" "" "" "" "0#
#"C"" "-2x" "" "" "" "" "-x" "" "" "" "+2x#
#"E"" "0.0250-2x" "" "0.0200-x" "" "" "2x#

Remember to include the coefficients in the #Delta[" "]#, and in the exponents. I could freely use #"M"#, as... well, anything divided by #1# is itself. So by knowing that #2x = "0.0162 M"#, we automatically get:

#color(blue)(K) = (2x)^2/((0.0250-2x)^2(0.0200-x))#

#= (0.0162)^2/((0.0250-0.0162)^2(0.0200-0.0162/2))#

#= color(blue)(285)#

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