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What is the derivative of #sqrt[arctan(x)]#?

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Jun 12, 2015

#d/(dx) sqrtu = 1/(2sqrtu) * (du)/(dx)#
#d/(dx) arctanu = 1/(1+u^2) * (du)/(dx)#

Putting them together:

#d/(dx)[sqrt(arctanx)] = 1/(2sqrt(arctanx))*1/(1+x^2)#

#= 1/(2(1+x^2)sqrtarctanx)#

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