What could the $""^(n)"Pr"$ mean in $""^(n)"PrNH"_2$ ?

Question

Is it "normal propyl", like in $n$ -pentane, or something else? $"Pr"$ as an atom is praseodymium, but is it possible that $""^(n)"Pr"$ is normal-propyl?

I've seen $""^(i)"Pr"$ indicate isopropyl before.

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Answer 1 · 2017-12-02T17:59:59

It is $"n-propyl"$ , where $n$ is short for $"normal"$ as you suspected....three carbon atoms in a straight chain...

And thus $"n-propyl"$ specifies the STRAIGHT CHAIN.... $H_3C-CH_2CH_2X$ , and isopropyl specifies the branched chain, $Pr^(i)-=-CH(CH_3)_2$ .

As for $"praesodymium"$ , I doubt any organic chemist could even find a lanthanide.....