How much 5.0 M HNO3 is needed to make 225ml of 1.0M HNO3?
1 Answer
Well, the easy way to do this is to realize that solute concentration and solution volume are inversely proportional.
Since you want to go from
#-> color(blue)"45 mL"# of#"5.0 M"# #"HNO"_3#
Again, by starting at
I suppose if you wanted to do it the hard way...
#M_1V_1 = M_2V_2#
#V_1 = M_2/M_1 V_2#
#= "1.0 M"/"5.0 M" cdot "225 mL" = "45 mL"# #color(blue)sqrt""#
But then, just using the equation, how do you know you don't have the concentration ratio upside-down? What happens to concentration and volume in a dilution?