How many molecules(not moles) of NH3 are produced from 4.90*10^-4 g of H2?

1 Answer
Truong-Son N.
Oct 22, 2017

Well, you should supply us this reaction straight from your textbook...

#3"H"_2(g) + "N"_2(g) -> 2"NH"_3(g)#

When you peer over at your periodic table, you'll find the molar mass of #"H"_2#, and you would then calculate its mols. You'll need to look at your chemical reaction as well to get the mol to mol ratio you need.

#4.90 xx 10^(-4) cancel("g H"_2) xx cancel("1 mol H"_2)/(2.016 cancel("g H"_2)) xx "2 mols NH"_3/(3 cancel("mols H"_2))#

#= 1.62 xx 10^(-4) "mols NH"_3#

Knowing that #"1 mol" = 6.022 xx 10^(23) "anything ever"#, how many molecules do you have? Should this number be huge or tiny? Ask yourself that before you do this calculation.

Related questions
Impact of this question
4112 views around the world
You can reuse this answer
Creative Commons License