How does the de-broglie wavelength of charged particle change when accelerating potential increases?
1 Answer
Feb 22, 2018
Well, the potential that accelerates the charged particle gives it a kinetic energy in
#lambda = h/(mv)#
for mass-ive particles. We know that the kinetic energy is
#K = 1/2 mv^2# ,
so
#v = sqrt(2K//m)#
This means for particles with mass,
#color(blue)(lambda) = h/(mcdot sqrt(2K//m))#
#= color(blue)(h/(sqrt(2mK)))#
We see that as
So, as the accelerating potential increases, the kinetic energy of the particle increases, the de Broglie wavelength decreases, and the particle acts more classically.
