How do you solve #9^(x-4)=81#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Alan P. Feb 12, 2015 #9^(x−4) = 81# implies #x = 6# The only value #p# for which #9^p = 81# is #p = 2# so #x-4 = 2# #rarr# #x=6# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? How do you solve #3^x=14#? See all questions in Logarithmic Models Impact of this question 4503 views around the world You can reuse this answer Creative Commons License