How do you evalute sin^-1 (-sqrt(3)/2)?

1 Answer
Oct 23, 2014

Let

theta=sin^{-1}(-sqrt{3}/2).

By rewriting it in terms of sine,

Rightarrow sin theta=-sqrt{3}/2

So, we need to find the angle theta between -pi/2 and pi/2 that makes sine equal to -sqrt{3}/2.

Since

sin(-pi/3)=-sqrt{3}/2,

we have

theta=sin^{-1}(-sqrt{3}/2)=-pi/3.


I hope that this was helpful.