How do you evalute $sin^-1 (-sqrt(3)/2)$ ?

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Answer 1 · 2014-10-23T21:46:57

Let

$theta=sin^{-1}(-sqrt{3}/2)$ .

By rewriting it in terms of sine,

$Rightarrow sin theta=-sqrt{3}/2$

So, we need to find the angle $theta$ between $-pi/2$ and $pi/2$ that makes sine equal to $-sqrt{3}/2$ .

Since

$sin(-pi/3)=-sqrt{3}/2$ ,

we have

$theta=sin^{-1}(-sqrt{3}/2)=-pi/3$ .

I hope that this was helpful.

How do you evalute sin^-1 (-sqrt(3)/2)sin^-1 (-sqrt(3)/2)?