How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer sjc Jun 28, 2018 #x^11/11-x^6+x^4/2+c# Explanation: using the power rule #intx^ndx=x^(n+1)/(n+1)+c,x!=-1# #int(x^10-6x^5+2x^3)dx# #=x^11/11-(6x^6)/6+(2x^4)/4+c# cancelling down we have #x^11/11-x^6+x^4/2+c# Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? What is the integral of #sqrt(9-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 1189 views around the world You can reuse this answer Creative Commons License