How do you evaluate the integral 3ex5e2xdx?

1 Answer
Sep 25, 2014

3ex5e2xdx=3ex52e2x+C

Let us look at some details.

Remember:

exdx=ex+C

ekxdx=ekxk+C

Now, let us work on the integral.

3ex5e2xdx

by applying integral on each term,

=3exdx5e2xdx

by pulling constants out of the integrals

=3exdx5e2xdx

by applying the formulas above,

=3ex5e2x2+C