Help me with the question below ????
1 Answer
Here's what you're starting with:
I'll tell you what I call them, but you'll have to figure out what you should be calling them...
You start with an alkene and end up with an alkane (a hydrocarbon with only single bonds).
You start with an alkene and form an alkyl dihalide (
#R-"X"# ), with two halide (#"X"^(-)# ) functional groups.
You start with an alkene and form an alkyl halide (
#R-"X"# ), with one halide (#"X"^(-)# ) functional group.
You start with an alkene and form an alcohol (
#R-"OH"# ), with a hydroxyl functional group (#"OH"# ).
You start with the alkyl halide and form an amine (
#R-"N"-R_1R_2# ), with an amine (#"N"-R_1R_2# ) functional group.
You start with the alcohol and replace the hydroxyl functional group with a chloride (
#"Cl"^(-)# ) functional group, just another type of halide. [The analogous reaction is using#"PBr"_3# to form an alkyl bromide instead.]
This begins with the carboxylic acid (with a carboxyl [
#"COOH"# ] functional group) and forms an ester (with a carboxylate [#"COO"-R# ] functional group).