Heat of fusion of ice is 6 kilo joule per mole , hence the entropy change for fusion of 10 g ice at 1 ATM is......?
1 Answer
Mar 20, 2018
Phase changes are phase equilibria at constant temperature and pressure. In that scenario,
#DeltaG_(trs) = 0 = DeltaH_(trs) - T_(trs)DeltaS_(trs)# where
#trs# stands for phase transition.
Hence, and I will use the correct enthalpy of fusion...
#DeltaS_(fus) = (DeltaH_(fus))/T_f#
#= ("6.02 kJ/mol")/("273.15 K") = "0.02204 kJ/mol"cdot"K"#
#= "22.0 J/mol"cdot"K"#
So then,
#color(blue)(DeltaS_(fus)) = "22.0 J"/(cancel"mol"cdot"K") xx cancel("1 mol H"_2"O")/(18.015 cancel("g H"_2"O")) xx 10.0 cancel("g H"_2"O") = color(blue)(???)#
