For the ion #"NH"_4^+# the conductance at infinite dilution and 50deg c is 115. The equivalent conductance of #"NH"_4"NO"_3# at 50deg c and infinite dilution is 219. What is the conductance of the ion #"NO"_3^-# at 50deg c and infinite dilution?
1 Answer
Mar 8, 2018
All we can really say here is that at the limit of infinite dilution, the ions don't see each other, so the conductivities they contribute to solution are additive. Therefore:
#Lambda_("NH"_4"NO"_3) = Lambda_("NH"_4^(+)) + Lambda_("NO"_3^(-))#
#219 = 115 + Lambda_("NO"_3^(-))#
I assume the units work out, but the question writer must supply the units...
#Lambda_("NO"_3^-) = 104# #["insert units here"]#
