How do I evaluate the indefinite integral intsin(x)/(cos^3(x))dx ?
1 Answer
Jul 30, 2014
=1/2*1/(cos^2(x))+c , wherec is a constantExplanation
=intsin(x)/(cos^3(x))dx Using Trigonometric Substitution,
let's assume
cos(x)=t ,=> -sin(x)dx=dt
=int-dt/t^3
=-intt^-3dt
=-t^-2/(-2)+c , wherec is a constantsubstituting back the value of
t ,
=1/2*1/(cos^2(x))+c , wherec is a constant
