#beta^-# decay problem?
In #beta^-# decay a neutron in a nucleus is transformed into a proton, an electron, and an antineutrino:
#n rarr p + e^(-) + barv #
(a) The physical quantity not conserved in #beta^-# decay is____
(b) The particle denoted by the question mark in the reaction
#N_7 ^(13)" rarr# #C _6 ^(13)" +e^(-) + ?#
is____.
Note that the superscript and subscript in #C _6 ^(13)"# , for instance, are respectively the mass number A and atomic number Z of the carbon nucleus.
In
(a) The physical quantity not conserved in
(b) The particle denoted by the question mark in the reaction
is____.
Note that the superscript and subscript in
1 Answer
As shown in the question, in
#""_(0)^(1) n -> ""_(1)^(1) p + ""_(-1)^(0) e + barupsilon# where
#""_(0)^(1)n# is a neutron,#""_(1)^(1) p# is a proton, and#""_(-1)^(0)e# is an electron.
Part (a) shows that the atomic number is not conserved in
In an explicit example, the question presents:
#""_(7)^(13) "N" -> ""_(6)^(13) "C" + ""_(-1)^(0) e + ?#
There may be a typo in the problem... clearly,
#""_(6)^(13) "C" -> ""_(7)^(13) "N" + ""_(-1)^(0) e + ?#
In THAT case, it would be an antineutrino. It IS true that
