A sample of oxygen occupies a volume of 160 dm3 at 91° C. What will be volume of oxygen when the temperature drops to 0.00° C?

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A sample of oxygen occupies a volume of 160 dm3 at 91° C. What will be volume of oxygen when the temperature drops to 0.00° C?

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Answer 1 · 2014-05-30T23:51:54

The volume of the oxygen will be 120 dm³.

This is an example of Charles' Law.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ $V_1/T_1 = V_2/T_2$

$V_{1}$ $V_1$ = 160 dm³; $T_{1}$ $T_1$ = (91 + 273.15) K = 364 K
$V_{2}$ $V_2$ = ?; $T_{2}$ $T_2$ = (0.00 + 273.15) K = 273.15 K

$V_{2} = V_{1} \times \frac{T_{2}}{T_{1}}$ $V_2 = V_1× T_2/T_1$ = 160 dm³ × $\frac{273.15 K}{364 K}$ $(273.15"K")/(364"K")$ = 120 dm³

This makes sense. The final Kelvin temperature was about 25 % lower than the initial temperature. The final volume should be about 25 % (40 dm³) less than the initial volume.

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A sample of oxygen occupies a volume of 160 dm3 at 91° C. What will be volume of oxygen when the temperature drops to 0.00° C?

1 Answer

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