For the rate law, #"rate" = k[A]^2[B]#, how do concentrations function when finding the units of the rate constant?

1 Answer
Truong-Son N.
Jan 24, 2018

Well, they multiply... for some rate law

#r(t) = k[A]^2[B]#,

if #r(t)# is in #"M/s"# and #[" "]# is in #"M"#, then

#"M/s" = kcdot("M"^2)cdot("M")#

and the rate constant here is in units of #"M"^(-2)cdot"s"^(-1)#:

#k = "M/s"/("M"^2 cdot "M")#

#= "M/s"/("M"^(2+1))#

#= "M"^(1 - (2 + 1)) cdot "s"^(-1)#

#= "M"^(-2)cdot"s"^(-1)#

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