Why is #e# the charge of the electron?
1 Answer
Jan 23, 2018
It's not, really.
#q_"proton" = e ~~ 1.602 xx 10^(-19) "C"#
#q_"electron" = -e = -1.602 xx 10^(-19) "C"#
It's not, really.
#q_"proton" = e ~~ 1.602 xx 10^(-19) "C"#
#q_"electron" = -e = -1.602 xx 10^(-19) "C"#