Question #964eb
1 Answer
I got
That changes the whole calculation. We then look at shielding via the
#S(4s) = 2 cdot overbrace(1.00)^(1s) + 2 cdot overbrace(1.00)^(2s) + 6 cdot overbrace(1.00)^(2p) + 2 cdot overbrace(0.85)^(3s) + 6 cdot overbrace(0.85)^(3p) + 5 cdot overbrace(0.85)^(3d) + 1 cdot overbrace(0.35)^(4s) = 21.4#
And from that,
#color(blue)(Z_(eff)) = 25 - 21.4 = color(blue)(3.6)#
For this we refer to Slater's rules for calculating
#Z_(eff) = Z - S# where
#Z# is the atomic number and#S# is the shielding constant. It's in#S# where all the little 'rules' come in.
We partition the orbitals as follows, in the so-called "Slater ordering of atomic orbitals":
#(1s)(2s,2p)(3s,3p)(3d)(4s,4p)(4d)(4f)(5s,5p)(5d)(5f)(6s,6p)(cdots)#
Their contributions to
s and p electron
#S = 0.35# if the electron is in an orbital of the same#n# . For a#1s# electron shielding another one, it is#0.30# .
#S = 0.85# if the electron is in an outer core orbital with#n-1# .
#S = 1.00# if the electron is in a deep core orbital (#n - 2# or below).d and f electron
#S = 0.35# if the electron is in a#d# or#f# orbital of the same#n# .
#S = 1.00# if the electron is an#s# or#p# orbital of the same#n# .
#S = 1.00# if the electron is in a deep core orbital (#n - 1# or below).
We have a
I don't know why you would want the
#S = 2 cdot overbrace(1.00)^(1s) + 2 cdot overbrace(0.85)^(2s) + 6 cdot overbrace(0.85)^(2p) + 1 cdot overbrace(0.35)^(3s) + 6 cdot overbrace(0.35)^(3p)#
#= 11.25#
And so, for the
#color(blue)(Z_(eff)) = 25 - 11.25 = color(blue)(13.8)#