What mass of copper is generated by electroplating as much copper as possible using #"96500 C"# of charge?
1 Answer
Oct 26, 2017
This is just a unit conversion. But it also depends on which copper ion you start with...
#"Cu"^(+)(aq) + e^(-) -> "Cu"(s)#
#color(blue)(m_(Cu)) = 96500 cancel"C" xx overbrace(cancel("1 mol e"^(-))/(96485 cancel"C"))^("Faraday's Constant") xx cancel("1 mol Cu"^(+))/cancel("1 mol e"^(-)) xx "63.546 g Cu"/cancel("1 mol Cu"^(+))#
#=# #color(blue)"63.6 g Cu"#
On the other hand...
#"Cu"^(2+)(aq) + 2e^(-) -> "Cu"(s)#
#color(blue)(m_(Cu)) = 96500 cancel"C" xx overbrace(cancel("1 mol e"^(-))/(96485 cancel"C"))^("Faraday's Constant") xx cancel("1 mol Cu"^(2+))/cancel("2 mol e"^(-)) xx "63.546 g Cu"/cancel("1 mol Cu"^(2+))#
#=# #color(blue)"31.8 g Cu"#
