Question #d1cdd
1 Answer
Oct 22, 2017
Well, each bond angle requires an angular distance between two atoms, across a central atom, i.e. an angle is
Therefore, one can keep the central atom constant and look at the permutations of two-atom combinations for the angle.
Denote outer atoms as
"O"_1-"C"-"O"_2 "O"_1-"C"-"O"_3 "O"_1-"C"-"O"_4 "O"_2-"C"-"O"_3 "O"_2-"C"-"O"_4 "O"_3-"C"-"O"_4
Ignoring redundant angle counting, we get