What shape is specified if the angular momentum quantum number #l = 6#? How many of these orbitals are in this subshell?

1 Answer
Truong-Son N.
Oct 25, 2017

First of all, you'll never see #10i# orbitals... ever. They are not known to man and probably never will be. The highest angular-momentum orbital we've observed is an #f# orbital. We still have not observed a #5g# orbital, but if an element forms with an atomic number of #121#, we might see that.

#10i# orbitals have the angular momentum quantum number #l = 6#, since #l = 0, 1, 2, 3, 4, 5, 6, 7, . . . # corresponds with the shapes #s, p, d, f, g, h, i, k, . . . #.

The degeneracy of a given atomic subshell is #2l+1#, so the number of #10i# orbitals is

#2(6) + 1 = 13#

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