If the density of an ethylene glycol solution is #"1.0241 g/mL"#, and ethylene glycol has a molar mass of #"62.07 g/mol"#, what is its molarity? The molality is #"16.11 L"#.

1 Answer
Truong-Son N.
Oct 14, 2017

If you know the density, you don't need the molality to find the molarity. [#m# means molality, i.e. #"mols solute/kg solvent"#.]

#color(blue)(["EG"]) = (1.0241 cancel"g EG")/cancel"mL" xx "1 mol"/(62.07 cancel"g EG") xx (1000 cancel"mL")/"1 L"#

#=# #color(blue)("16.50 M")#

Even if the cited molality was a volume, it wouldn't matter because molarity is intensive.

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