Question #2028e

1 Answer
Oct 6, 2017

The mol is just a way to count a lot of things, and we designate the number of things in #"1 mol"# the name Avogadro's number:

#"1 mol" = 6.022 xx 10^23# whatchamacallits

And so, to get your units to cancel out, let these whatchamacallits be atoms. You can then get:

#1.79 xx 10^24 cancel"C atoms" xx "1 mol"/(6.022 xx 10^23 cancel"C atoms")#

#=# #color(blue)("2.97 mols C")#

A common error is to either not put parentheses when dividing, giving something huge, or multiplying by Avogadro's number to get something really huge.

[Either put parentheses in your calculator or use #"E"# notation.]

A #"mol"# of something should always be manageably small, i.e. #"0.5 mols"#, #"15 mols"#, etc.