What is the #"pH"# for an aqueous solution with #["H"^+] = 7.5 xx 10^(-3) "M"#?
1 Answer
Aug 10, 2017
Well, you ought to memorize that
#"pH" = -log["H"^(+)]# .
Thus, apply the definition to get...
#"pH" = -log(7.5 xx 10^(-3) "M") = ???#
What is another way to write
