Why are there no electronic transitions in #"He"^(2+)#?

1 Answer
Truong-Son N.
Jul 9, 2017

Well, because it has no electrons... And hence there can be no electronic transitions to speak of. But #"He"^(+)# is another story. Why?

The Bohr model of course cannot apply... its very definition models the atom as a positively-charged nucleus surrounded by electrons that travel in circular, fixed orbits (that violate the Heisenberg Uncertainty Principle).

https://upload.wikimedia.org/

At least hydrogen atom has one electron. But #"He"^(2+)# has none. Zero.

#"He": 1s^2#

#=> "He"^(2+): 1s^0#

Why does the Bohr model apply to #"He"^(+)#?

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