What is the reference angle for #t = 4.5#?

1 Answer
Jun 19, 2017

Assuming #t = 4.5# means #"4.5 rad"#, I get #77.8^@# counterclockwise from negative x axis.


Well, assuming #t = 4.5# means #"4.5 rad"#, we know that there are #pi# radians for every #180^@#, so:

#4.5 cancel"rad" xx (180^@)/(pi cancel" rad") = 257.8^@#

The reference angle, though, is the smallest angle you can make from the #x# axis. So, we need this angle to be less than #180^@#.

If we start from the positive #x# axis (bisecting quadrants I and IV), then we are currently in quadrant III (bottom-left). Since quadrant III starts at #180^@# counterclockwise from the positive #x# axis, our reference angle is:

#257.8^@ - 180^@ = color(blue)(77.8^@)# counterclockwise from negative x axis

Another example is if the given angle was #250^@#. Then the reference angle would be #70^@# counterclockwise from the negative #x# axis:

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