Which of the following is established under the postulates of quantum mechanics about the real wave function #Psi#, where #P# is the probability of finding a particle whose time-dependent state is described by #Psi# in volume #dV#?
#A)# #int Psi^2dV < 0#
#B)# #int Psi_nPsi_mdV = 1#
#C)# #int Psi^2dV = 1#
#D)# #int Psi^2dV = 0#
2 Answers
(C)
Explanation:
The wave function
The relationship is:
If we integrate
If we integrate over all space, the probability must be 1.
NORMALIZABILITY OF ANY WAVE FUNCTION
Two of the quantum mechanics postulates jointly say that the wave function must be orthonormal over allspace, so it must be normalized. Normalized means its probability density goes from
If you are talking about spherical harmonics, then yes, allspace is basically
#\mathbf(Psi(r,theta,phi) = R_(nl)(r)Y_(l)^(m)(theta,phi))# where:
#R_(nl)(r)# is the radial component of the wave function that describes distance from the center of a sphere outwards to infinity (#n# and#l# are the quantum numbers#n# and#l# )#Y_(l)^(m)(theta,phi)# is the angular component that may contain a dependence on#theta# , or may contain a dependence on both#theta# AND#phi# .
In that case, the radial component,
As a sidenote, a particle in a box model DOES show allspace as
CONDITIONS FOR A PHYSICALLY REALISTIC WAVE FUNCTION
For the time-dependent wave function
- The wave function must be closed (it must have boundary conditions).
- It must be single-valued (i.e. it must pass the vertical line test).
- It must be continuous.
#int_"allspace" Psi^"*"Psid tau = 1# , i.e. it must be normalizable over allspace.#int_"allspace" Psi_A ""^"*" Psi_Bd tau = 0# , i.e. two different wave functions must be orthogonal to each other.
ORTHONORMALITY OF THE 2P ORBITAL WAVE FUNCTIONS
For instance,
I've shown the normalizability of the
http://socratic.org/scratchpad/02f319af3fee9184eb68
All that says is that the probability of finding an electron anywhere within a
You can visually recognize the orthogonality by realizing that the x and y axes are perpendicular, and these atomic orbitals lie along those axes. Hence, their dot product is
I've also done a proof of the orthogonality here for the
http://socratic.org/scratchpad/d92580b37cb5a5249f5d