What is the final height in meters a rising object reaches if its initial velocity is #"50 m/s"# and it takes #"7 s"# to get there?

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Answer 1 · 2015-10-10T00:59:57

Let's consider the kinematics equation for 1-dimensional, directly-upwards motion:

#y_f = -1/2g t^2 + v_(iy)t#

where we assume that the height at which it starts is #0#.
(Here, #g > 0#.)

When we plug in #"7 s"#, we get:

#y_f = -1/2(9.80665) (7)^2 + (50)(7)#

#= color(blue)("109.74 m")#

If your teacher/professor cares about sig figs, round it down to #"100 m"#.