Why is blue light scattered more than red light?

1 Answer
Sep 10, 2015

That is described by:

#I = I_0 (1+cos^2theta)/(2R^2)((2pi)/lambda)^4 ((n^2-1)/(n^2+2))^2 (d/2)^6#

where #I# is the Rayleigh light scattering intensity.

Simplifying the expression to see what's important, we just get:

#I prop 1/(lambda^4)#

That means the greater/longer the wavelength, the less intensely the light scatters, and so the smallest/shortest wavelength you can see is scattered the most.

The shortest wavelength that scatters is violet. The shortest wavelength you can see is blue. However, blue is scattered less intensely than violet due to its longer wavelength (smaller frequency, lower energy, lower intensity), so not seeing violet doesn't mean you see a dark blue sky---you see a light blue sky, which is merely due to not all of the dark blue light scattering.

http://www2.chemistry.msu.edu/

You can see here that red is near #"700 nm"# but blue is nearer #"400 nm"#.