What is the length of an arc that has an angle of #100^@# and radius of #"10.0 m"#?

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Answer 1 · 2015-08-28T01:56:14

The "length of an arc" can be found using:

#s = rtheta#

where #s# is arc length, #r# is the distance to the axis of revolution, and #theta# is the angle swept through.

Converting #100^o# to radians:

#100^o xx (pi "rad")/(180^o) = (5pi)/9 "rad"#

And now just plug it in:

#s = ("10.0 m")((5pi)/9 "rad") = color(blue)((50pi)/9 "m")#