For what #n# does #y = x^n# contain the points #(2,200)# and #(2,2000)#?

1 Answer

Unless there is a typo:

Using the given polynomial, which is a single-valued monomial, there can only be one value of #y# for every value of #x#.
Using the given coordinates, the equation is claimed to have two values of #y# for the value of #x=2#.
Therefore, no such #n# exists that correlates the two coordinates with this single-valued polynomial.