1.32g of unknown nonelectrolyte is dissolved in 428g of cyclohexane, lowering freezing point from 6.50 degree Celsius to 3.91 degree Celsius. The molal freez point constant of cyclohexane=20.2 degree Celsius/m. What is molar mass of unknown nonelectrolyt?
help with steps please!!
help with steps please!!
1 Answer
#M_m = "24.1 g/mol"#
Freezing point depression is given by:
#DeltaT_f = T_f - T_f^"*" = -iK_fm# ,where:
#T_f# is the freezing point of the solution.#"*"# indicates pure solvent.#i# is the van't Hoff factor, i.e. the number of dissociated solute particles per undissociated solute particle.#K_f# is the freezing point depression constant of the solvent.#m# is the molality of the solution, i.e.#"mol solute/kg solvent"# .
We want the molar mass, and the first thing we can find is the molality.
#m = (DeltaT_f)/(-iK_f)#
We have that
Therefore, the molality is:
#m = (3.91 - 6.50^@ "C")/(-(1)(20.2^@ "C"cdot"kg/mol"))#
#=# #"0.128 mol solute/kg solvent"#
There are
#"0.128 mol solute"/cancel"kg solvent" xx 0.428 cancel"kg solvent"#
#=# #ul"0.0549 mols solute"# dissolved in it.
As a result, knowing that we dissolved
#color(blue)(M_m) = "1.32 g solute"/"0.0549 mol solute" = color(blue)ul("24.1 g/mol")#